Question

Example 11.1 A force of 5 N is acting on an
object. The object is displaced through
2 m in the direction of the force (Fig.
11.2). If the force acts on the object all
through the displacement, then work
done is 5 Nx2 m =10 Nm or 10 J.
2 12
5 N-
Fig. 11.2​

Answer 1

Answer:

work done = ?

force, F = 5N

object get displaced in distance = 2m

to find work , W = F*

so,

W=5N*2m

W= 10J