Question

Example 11
An electric iron consumes
iron consumes energy at a rate of 840 W when heating
the maximum rate and 360 W when the heating is at the
The voltage is 220 V. What are the current and the
minimum. The voltage is
resistance in each case?​

Answer 1

We know that the power input is (P) = VI

Thus, the current, I = P/V

When heating is at the maximum rate,

            I = 840W/220V = 3.82 A

and the resistance of the eletric iron is

           R = V/I = 220V/3.82A = 57.59 ohm

When heating is at the minimum rate,

            I = 360W/220V = 1.64 A

and the resistance of the electric iron is

           R = V/I = 220V/1.64A = 134.15 ohm

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HOPE THE ANSWER IS CORRECT

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Answer 2

Explanation:

you are requested to write your answer in your notebook