Question

Example 11: Find the area of a triangle whose vertices are (1, -1), (- 4, 6) and
(-3,-5)
Please tell me fast

Answer 1

Refer the attachment.......

Answer 2

Answer:

24 sq. units

Step-by-step explanation:

let the points be A(1,-1) ,B(-4,6), C (-3,-5)

we know area of trianhle is given by

1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

here

x1=1, y1=-1

x2=-4, y2=6

x3=-3, y3=-5

putying all the given values in the above formula

we get,

1/2[(1)(6+5) +(-4)(-5-(-1)) +(-3)(-1-6)]

=1/2[1(11)+(-4)(-4) +(-3)(-7)]

=1/2[11+16+21]

=1/2[48]

=24 sq. units