Question

Example 11 : Find two consecutive odd positive integers, sum of whose squares
is 290.​

Answer 1

Answer:

11 and 13

Step-by-step explanation:

11^2+13^2= 121 + 169 =290

Answer 2

Answer:

Let x an odd positive integer

Then, according to question

x² + ( x + 2 ) = 290

2x² + 4x - 286 = 0

x² + 2x − 143=0

x² + 13x − 11x − 143=0

( x +13 ) ( x + 11 ) = 0

x = 11 as x is positive

Hence required integers are 11 and 13.

Step-by-step explanation:

I hope it's helpful for you.