Question

Example 11. In a box, there are some coins of valuation 1rupee,50 paise and 25 paise
and their total number is 450. If the ratio of the total prices of these coins be
8: 5:3, then find the number of each type of coin in the box.
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Answer 1

Step-by-step explanation:

let no. of coins of each value =x

No. of 1 rupees coins =8*1 x=8x

no. of 50 paise coins =5*50/100x=2.5x

no. of 25 paise coins = 3*25/100x=0.75x

total value of money = rupees 450

8x+2.5x+0.75x=450

11.25x=450

x=450*100/1125

x=45000/1125

x= 40

No. of 1 rupees coins=8*40=320

No. of 50 paise coins =5*40=200

No. of 25 paise coins =3*40=120