Question

Example 12.6 of physics class 10 chapter electricity

Answer 1

Answer:

Explanation:

Each of the resistors in parallel combination has the same potential difference across them; current flows as per the value of resistance in them. This happening can be explained with the example of the flow of water through different pipes. If multiple pipes are connected to the tank, water flows as per the thickness of the pipe. If the thickness of the pipe is more, more water can flow through them. Similar things happen with resistors; if the resistor is of lower resistance more current flow through them and if the resistance is high lesser current flows through them.

Here total current flow I= I1 + I2 + I3

I1:I2:I3 = 1/R1:1/R2:1/R3

This result can also be achieved through Ohm’s law, v=IR

Here potential difference across the all the resistors  are same,

so,

V= I1*R1 = I2*R2 = I3*R3

Inference/conclusion:

This experiment demonstrates current in different resistors in parallel have different values.

note:

Resistors in parallel can be assumed as a single resistor R, where R equals to

1/R = 1/R1 + 1/R2 + 1/R3

Application:

In our home electricity comes as 240v AC. Here, all the appliances act as resistors of different value and consume energy as per their requirement.

Answer 2

Answer:

this is from physics 10th science book cbse