Example 12: A 1000 kg engine pulls a train of 4 wagons each of 2500 kg along a horizontal railway track. If the engine exerts a force of 50000 N on wagons and track offers a force of fiction of 2500 N on each wagon, then calculate (i)The net accelerating force (ii) the acceleration of the train (iii) the force by Wagon 1 on wagon 2 I am unable to understand the solution to this question given below.
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Answer:
forget everything now (^.^).. i will say u the qn and answer
dude there is a train , Its engine is generally at front size ...so it should Pull the wagons with some force , and at the same time due to the Surface fractional force is excerted .
We wanna find acceleration So forumala is Fnet = Ma
Fnet means total force on body ( train here )
u can clearly find that Force and friction are opposite to each other so net force is
Fnet = Force BY ENGINE - Friction
so total mass of train and net force we got ..we found acceleration
so last qn he's asking .... Train has 4 wagons ... so as train engine pulls ...first force excerts on 1st wagon rest all . so as it first wagon pulls ....rest wagons Also excerts opposing force...hes asking to calculate opposing force
so form newton law Fnet = Ma
= Mass of 3 wagons × Acceleration