Example 13. How many three-digit
numbers are divisible by 7?
Answers
Answer:
∴ There are 128 3-digits number which are divisible by 7.
Hi Dear Friend
Your answer (My own answer, not searched in web)
Number divisible by 7
Lowest 3 digit number: (check whether divisible by 7)
100/7 = 14.2857143
101/7 = 14.4285714
102/7 = 14.5714286
103/7 = 14.7142857
104/7 = 14.8571429
105/7 = 15
So it is the lowest 3 digit number divisible by 7
Highest 3 digit number:
999 = 142.714285714
998 = 142.571428571 (997,996,...)
994 = 142
So it is the highest 3 digit number divisible by 7
Hence, the series starts with 105 and end at 994
We need to find the number of terms:
Lets use a formula
T(n) = a + (n – 1) d
Let a = 105, d = 7,
T(n) = 994
994 = 105 + (n – 1) 7
889 = 7n – 7
7n = 896
n = 128
Therefore there are 128 3 digit number that is divisible by 7
Hope my answer is helpful