Question

Example 18. If one zero of the polynomial
2x2 – 5x – (2k + 1) is twice the other, then find both the
zeroes of the polynomial and the value of k.

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Answer 1

Answer:

2x^2 - 5x -(2k+1)

alpha = 2beeta

sum of zeroes

2 beeta + beeta = -b/a

= 5/2

3beeta = 5/2

6beeta = 5

beeta = 5/6

prod. of zeroes

alpha * beeta = -( 2k+1)/2

aplha * 5/6 = -2k-1/2

10 alpha = -12k-6

alpha = -6(2k + 1)/10

alpha = -3 (2k+1)/5

Answer 2

Answer:

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