Question

Example 19.
A ball thrown from ground at an angle = 37° with speed u = 20 m/s collides with a vertical wall 18.4 meter
away from the point of projection. If the ball rebounds elastically to finally fall at some distance in front of the
wall, find for this entire motion. (i) maximum height (ii) time of flight (ili) distance from the wall where the ball
will fall (iv) distance from point of projection, where the ball will fall.

Answer 1

Answer:

Explanation:

Let (u) be the velocity of projection from (O) at an angle 45∘, which just clears the top(A)of wall of height (h) Fig. 2 (d) .23.`

.

Given, horizontal range =15+5=20m

So (u∘)sin2θ)g=20

or u2sin2×45∘g=20

or u2g=20

Let (x, y) be the coordingates of (A), the

x=15mandy=h.

Using the equation of trajectory, we have y=xtanθ−12gx2u2cos2θ

h=15tan45∘−12×(15220×12=3.74m.

Answer 2

Explanation:

see the detailed solution of this projectile problem ...