Question

Example 2.12 What volume of 95% sulphuric acid
(density = 1.85 g cm ) and what mass of water must
be taken to prepare 100 cm of 15% solution of sulphuric
acid (density = 1.10 g cm )?​

Answer 1

Explanation:

Mass = volume* density

volume=100 cm3

density=1.10 g/cm3

mass of 15% solution = 100*1.10=110 g

mass of sulphuric acid in it =.15*110=16.5g

mass of water present in it =110-16.5=93.5 g of water

95% solution

let mass of 95% solution required to prepare 15% H2SO4 with 16.5 g acid in it be x

16.5g =0.95* x

x=16.5*100/95 =17.4 g

Volume of 95%H2SO4 needed to prepare 15%H2SO4

VOLUME =mass/density

Volume =17.4/1.85= 9.4 cm3

Volume water needed to make up the volume =100-9.4=90.6 cm3