Physics, asked by umapatil11041974, 10 months ago


Example 2.2: A swimmer is swimming in
a swimming pool at 6 m below the surface
of the water. Calculate the pressure on the
swimmer due to water above. (Density of
water = 1000 kg/m², g=9.8 m/s-)​

Answers

Answered by dualadmire
20

Given:

Distance of the swimmer from the surface of water = 6 m

Density of water = 1000 kg/m²

g = 9.8 m/s²

To find:

The pressure exerted on the swimmer due to the water above.

Solution:

Pressure exerted = p*g*h

where p = density of water

g = acceleration due to gravity

h = height of water

Pressure = 1000* 9.8 * 6

=58,800 Pa = 0.588 atm

As 1 atm = 10⁵ Pa

Therefore, the pressure exerted by water on the swimmer will be 58,800 Pa or 0.588 atm.

Answered by siddkamble02
0

Answer:

d= 6 m

p= 1000 kg/m^2

g= 9.8 m/s^2

P= dpg

= 1000 kg/m^3 ×6m×9.8m/s^2

= 5.88×10^3kg/ms^2

=0.588×10^5 N/m2

.°. P= 0.588

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