Question

Example 2.25 Resolve into partial fractions:
Basic Algebra
(x+3)(x - 4)
А
B
where A and B are constants.
Solution:
I
+
Let
(2+3)(I - 4) 2 + 3
A(x - 4) + B(x+3)
(r +3)(- 4)
which gives x =
A(x - 4) + B(x+3)
Then,
(2+3)(2-4)
When r = 4. we have B
7
3
When I = -3, we have A
3
4
+
Hence, ,
(x+3)(r - 4) 7(x+3) 76.1 – 4)​

Answer 1

Answer:

Explanation:

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