Example 2.26 Find the number of terms in the A.P. 3, 6, 9, 12,..., 111.
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Answer:
37
Step-by-step explanation:
Clearly, the given sequence is an A.P. with first term a = 3 and common difference d = 3. Let there be n terms in the given sequence. Then,
nth term = 111
a+(n−1)d=111
3+(n−1)×3=111
n=37
Thus, the given sequence contains 37 terms.
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