Example 2 : AB is a line segment and line lis its perpendicular bisector. apore
lies on 1, show that Pis equidistant from A and B.
AD and BC.
Therefore,
AD || BC.
1
which
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hope it will help u
Step-by-step explanation:
Line l⊥AB and passes through C which is the midpoint of AB
To show that PA=PB
In △PCA and △PCB
AC=BC since C is the mid-point of AB
∠PCA=∠PCB=90∘(given)
PC=PC(common)
So,△PCA≅△PCB by SAS rule.
and so PA=PB as they are corresponding sides of congruent triangles.
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