Chemistry, asked by ATHARGAPALIWAL, 7 months ago

Example 2. Calculate the root mean square velocity and average speed of nitrogen at 27°C and 700
mm pressure.
Fron
700 mm pressure​

Answers

Answered by sonalgurjar
2

Explanation:

27

C=300 K

Root mean square speed =

M

3RT

R=8.314×10

7

erg K

−1

mol

−1

;M=32 g mol

−1

;T=300 K

Substituting the values,

=

32

3×8.314×10

7

×300

=483.56 cm/sec

=483.56 m/sec

Average speed =

πM

8RT

=

22×32

8×8.314×10

7

×300×7

=445.42 cm/sec

=445.42 m/sec

Most probable speed =

M

2×R×T

=

32

2×8.314×10

7

×300

=39482 cm/sec

=394.83 m/sec.

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