EXAMPLE 2 Consider Z10 under addition modulo 10. Since 1:2 =
2, 2 - 2 = 4,3 · 2 6, 4.2 8,5
2 = 0, we know that 121 = 5.
Similar computations show that 101 = 1, 171 = 10, 151 = 2,161 = 5.
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