Example 2 : If 6 litres of hydrogen and
5-6 litres of chlorine are mixed and exploded,
what will be the composition by volume of the
resulting gaseous mixture ? Name the limiting
reagent.
Answers
The reaction involved is,
H
2
+Cl
2
→2HCl
means 1 mole or 1 litre of H
2
needs 1 mole or 1 litre of Cl
2
to react completely and will form 2lit of HCl.
Since we have H
2
= 6 litre and Cl
2
= 5.6 litre, so their is Cl
2
present in insufficient amount.
Hence, limiting reagent is Cl
2
.
So, the reaction will involved reaction between 5.6 litre of Cl
2
with 5.6 litre of H
2
and 0.4 litre of H
2
will remain unreacted.
Hence, 5.6 litre of Cl
2
will produce,
5.6×2 = 11.2 litre of HCl.
Answer:
The reaction involved is,
H
2
+Cl
2
→2HCl
means 1 mole or 1 litre of H
2
needs 1 mole or 1 litre of Cl
2
to react completely and will form 2lit of HCl.
Since we have H
2
= 6 litre and Cl
2
= 5.6 litre, so their is Cl
2
present in insufficient amount.
Hence, limiting reagent is Cl
2
.
So, the reaction will involved reaction between 5.6 litre of Cl
2
with 5.6 litre of H
2
and 0.4 litre of H
2
will remain unreacted.
Hence, 5.6 litre of Cl
2
will produce,
5.6×2 = 11.2 litre of HCl.
Explanation:
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