Example 2 If a triangle and a Posialielogesam
are on the same base and between the same
and op to
A
Parallell, then Prove that the area of the
triangle is equal to half the area of the
pesialbloggam.
E
D
B
B
Answers
Answer:
example 2 for triangle of a pose syllogism
Step-by-step explanation:
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Step-by-step explanation:
To prove: Triangles on the same and between same parallel is equal in are.
Proof: △ABC & △ABD are drawn on the same base AB as base lying between the same two parallel lines L
1
& L
2
.
Here we will be using the following property of a triangle and parallelogram drawn on the same base between two parallel lines.
Since △ABC & ∣∣gm ABPQ are on the same base and between the same parallel L
1
& L
2
.
∴ar(△ABC)=
2
1
area of parallelogram ABPQ.
Similarly,
ar(△ABD)=
2
1
area of parallelogram ABPQ.
∴ area of △ABC=area of △ABD.
solution