Question

Example-2. In AABC and APQR, if angleA and angleP are acute angles such that sin A=sin P then
prove that angleA=angleP​

Answer 1

ANSWER

Given sinA=sinP

∴

AC

BC = PRRQ

Let RQ = PR AC =k

BC=kRQ and AC=kPR

Now,PQAB= PR 2 −RQ 2

AC 2−BC 2

PQ AB = PR 2−RQ 2

∴△ABC∼△PQR [By SSS similarity]

∴∠A=∠P