Question

Example 2 : In Fig. 6.10, ray OS stands on a line POQ. Ray OR and ray OT are
angle bisectors of Z POS and Z SOQ, respectively. If Z POS = x, find Z ROT.
Solution : Ray OS stands on the line PO​

Answer 1

Solution:

Ray OS stands on the line POQ.

therefore,

∠POS + ∠SOQ = 180°

But,

∠POS = x

Therefore,

x + ∠SOQ = 180°

So,

∠SOQ = 180° - x

Now, ray OR bisects ∠POS, therefore,

∠ROS = 1/2 × ∠POS

= 1/2 × x = x/2

∠SOT = 1/2 × ∠SOQ

= 1/2 × (180°-x)

= 90° - x/2

Now,

∠ROT = ∠ROS + ∠SOT

= x/2 + 90° - x/2

= 90°

Answer 2

Step-by-step explanation:

reffer to the attachment....

minatian~