Question

Example 2 : Pravin has applied a force of
100 N on an object, at an angle of 60° to
the horizontal. The object gets displaced in
the horizontal direction and 400 J work is
done. What is the displacement of the
object?
(cos 60° = 1)​

Answer 1

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Explanation:

work done is equal to force*displacement *cos   degree.

Here work done is 400 joule.

applied force is 100 N.

angle is 60 degree.

w=F*D*cos degree

400=100*D*1/2 ( value of cos 60 degree is 1/2)

50 D=400

D=400/50

Displacement is 8 m.