Example 2. Test for linear dependency of the following set of vectors: [1, 0,-1], [2, 1, 3). [-1.0, 0], [1, 0, 1) .
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Answered by
0
Narad T.
Jul 9, 2018
Please see the explanation below.
Explanation:
The vectors are
{
(
1
,
2
,
−
1
)
,
(
2
,
4
,
6
)
,
(
0
,
0
,
−
8
)
}
The vectors are independent if
α
⎛
⎜
⎝
1
2
−
1
⎞
⎟
⎠
+
β
⎛
⎜
⎝
2
4
6
⎞
⎟
⎠
+
γ
⎛
⎜
⎝
0
0
−
8
⎞
⎟
⎠
=
⎛
⎜
⎝
0
0
0
⎞
⎟
⎠
Where
α
,
β
,
γ
∈
R
3
has only the trivial solution
α
=
β
=
γ
=
0
Perform a row reduction on the augmented matrix
A
=
⎛
⎜
⎝
1
2
0
∣
0
2
4
0
∣
0
−
1
6
−
8
∣
0
⎞
⎟
⎠
⇔
,
R
2
←
R
2
−
2
R
1
⎛
⎜
⎝
1
2
0
∣
0
0
0
0
∣
0
−
1
6
−
8
∣
0
⎞
⎟
⎠
⇔
,
R
2
↔
R
3
⎛
⎜
⎝
1
2
0
∣
0
−
1
6
−
8
∣
0
0
0
0
∣
0
⎞
⎟
⎠
⇔
,
R
2
←
R
2
+
R
1
⎛
⎜
⎝
1
2
0
∣
0
0
8
−
8
∣
0
0
0
0
∣
0
⎞
⎟
⎠
⇔
,
R
2
←
R
2
8
⎛
⎜
⎝
1
2
0
∣
0
0
1
−
1
∣
0
0
0
0
∣
0
⎞
⎟
⎠
⇔
,
R
1
←
R
1
−
2
R
2
⎛
⎜
⎝
1
0
2
∣
0
0
1
−
1
∣
0
0
0
0
∣
0
⎞
⎟
⎠
Since there is a free variable, the system is not linearly independant
The determinant of the matrix
=
0
Therefore,
⎧
⎪
⎨
⎪
⎩
α
=
−
2
γ
β
=
γ
γ
=
free
So,
−
2
γ
⎛
⎜
⎝
1
2
−
1
⎞
⎟
⎠
+
γ
⎛
⎜
⎝
2
4
6
⎞
⎟
⎠
+
γ
⎛
⎜
⎝
0
0
−
8
⎞
⎟
⎠
=
⎛
⎜
⎝
0
0
0
⎞
⎟
⎠
Hope that this will help!!!
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