Question

Example 21: Find the amount and Cl for ₹100 at the rate of 10% compounded half-yearly for 1 whole 1/2 years.
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Answer 1

Step-by-step explanation:

QUESTIONS:-

Find the amount and Cl for ₹100 at the rate of 10% compounded half-yearly for 1 whole 1/2 years.?

ANSWER:-

Given that,

principal=100.

rate(r)=10%.

time = 1years.

we know that,

$compound \: interest = a - p \\ p = ({1 + \frac{r}{100}})$

As it is compounded half yearly

$Rate = \frac{r}{2}$

$Time = 2^{n}$

So,

$C.I. = p(1 + \frac{r}{100 \times 2} ) ^{2 ^{n} } - p$

$= > 100(1 + \frac{10}{100 \times 2} ) ^{2} - 100$

$= > \: 100( \frac{21}{20})( \frac{21}{20}) - 100$

$= > \frac{441 \ - \: 400 }{4}$

$= > \frac{41}{4}$

$= rs \: 10.25$

Therefore C.I.= RS.10.25

Hope It's helpful