Question

Example 3.1
A car is moving along a
straight line, say OP in fig.3.1 It moves
from O to Pin 18 s and returns from P to
in 6.0 s. What are the average velocity
and average speed of the car in going (a)
from 0 to P ? and (b) from 0 to P and back
to Q?

FROM 11TH NCERT BOOK PAGE NO. 43 PLEASE EXPLAIN CLEARLY :-)​

Answer 1

NOTE: SEE THE ATTACHMENT BELOW ↓↓

HOPE IT HELPS

MARK ME BRAINLIEST ^_^

Answer 2

$\huge\bold\red{ANSWER }$

$\bold{Answer \: (a)}$

Average velocity = $\frac{Displacement}{Time \: interval}$

v = $\frac{+ 360 m}{ 18 s}$

= +20m/s

Average speed = $\frac{Path\: length}{Time\: interval}$

= $\frac{360 m}{18 s}$

= 20 m/s

Thus, in this case the average speed is equal to the magnitude of average velocity.

$\bold{Answer \: (b)}$

Average velocity = [tex\frac{Displacement}{Time\: interval} [/tex]

= $\frac{360 m}{(18+6)s}$

= 10 m/s

Average speed = $\frac{Path\: length}{Time\: interval}$

= $\frac{OP+ PQ}{del(t)}$

= $\frac{(360+120)m}{24 s}$

= 20 m/s

Thus, in this case speed is not equal to magnitude of average velocity.

$\Huge\mathbb{THANKYOU!}$