Physics, asked by pihu892, 8 months ago

EXAMPLE 3.11: A man weighs 600 N on the earth. If acceleration due to gravity g on the
10 m s -2, what is his mass?
On the moon, weight of the man is found to be 100 N. What is the value of g on the moc​

Answers

Answered by BrainlyConqueror0901
16

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Value\:of\:g\:on\:moon=\frac{5}{3}\:m/s^{2}}}}\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt: \implies Weight \: of \: man \: on \: earth = 600 \: N\\  \\  \tt:  \implies Acceleration \: due \:to \: gravity(g) = 10 { \: m/s}^{2}  \\  \\  \tt:  \implies Weight \: of \: man \: on \: moon = 100 \: N \\  \\ \red{\underline \bold{To \: Find :}} \\  \tt:  \implies Value \: of \: g \: on \: moon =?

• According to given question :

 \bold{For \: weight \: of \: man \: on \: earth} \\  \tt:  \implies  Weight \: of \: man \: on \: earth = mg \\  \\  \tt:  \implies 600 = m \times 10 \\  \\  \tt:  \implies m =  \frac{600}{10}  \\  \\   \green{\tt:  \implies m = 60 \: kg} \\  \\  \bold{For \: weight \: of \: man \: on \: moon} \\   \\  \tt \circ \: Mass \: of \: man \: is \: constant   \\  \tt:  \implies Weight \: of \: man \: of \: moon = mg_{1} \\  \\  \tt:  \implies 100 = 60 \times  g_{1} \\  \\  \tt:  \implies g_{1} =  \frac{100}{60}  \\  \\ \tt:  \implies g_{1} = \frac{10}{6}  \\  \\  \green{\tt:  \implies g_{1} = \frac{5}{3}  \:  {m/s}^{2}}

Answered by Saby123
50

Question  -

A man weighs 600 N on the earth.

If acceleration due to gravity g on the

10 m s -2, what is his mass?

On the moon, weight of the man is found to be 100 N.

What is the value of g on the moc​n?

Solution -

In the above question, the following information is given -

A man weighs 600 N on the earth.

The, acceleration due to gravity g on the  surface Of The Earth is  10 \: m  . {s}^{-2}

We know that ,

According to The Newton's Laws Of Motion,

\sf{ \color{\teal} { F = m \times a }} \\ \\ \sf{\leadsto {  Where \: - }} \\ \\  \tt{ F \: is \: the \: Force } \\ \\ \tt{ m \: is \: the \: mass \: of \: the \: object } \\ \\  \sf{ a \: is \: the \: acceleration }

Now. Here -

Substuting The Required Values -

Weight = m * g

=> 600 = m * 10

=> m = 60 kg.

Hence, the required mass of the man on earth is 60 kg.

Now,

On the moon, weight of the man is found to be 100 N .

Let the acceleration due to gravity on the moon  be k

Using the similar relation mentioned above -

100 = 60 * k

=> k = [ 100 / 60 ] = [ 5 / 3 ] m . s^( -2 ) .

So, the value of acceleration due to gravity on the moon is [ 5 / 3 ] m . s^( -2 )  .

Answer

The value of acceleration due to gravity on the moon is [ 5 / 3 ] m . s^( -2 )  .

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