Math, asked by murugeshanshriram, 4 months ago

Example 3.51 : How many ways are there to select 8 balls from 50
red, 25 blue and 30 green balls ? How many selections include at least 3
green balls 2​

Answers

Answered by tripathiakshita48
0

Answer:

The correct answer is 35,20

Step-by-step explanation:

From the above question,

We need to find how many ways are there to select 8 balls from 50

red, 25 blue and 30 green balls.

A box contains 6 red balls, 5 blue balls, and 10 green balls. In how many ways can you choose 3 blue balls and 3 green balls?

Answer:

The number of ways  3 blue balls and  3 green balls can be choosen is  1200.

Step-by-step explanation:

Given:

6 red balls, 5 blue balls, and 10 green balls are contained in the box.

To Find:

The number of ways  3 blue balls and 3 green balls can be choosen.

Solution:

As given- 6 red balls, 5 blue balls, and 10 green balls are contained in the box.

The number of way to choose 3 blue balls out of 5 blue ball  

The number of way to choose  3 green  balls from 10 green balls    

The number of ways  3 blue balls and  3 green balls can be choosen  

Thus, the number of ways  3 blue balls and 3 green balls can be choosen is 1200.

3 red balls out of 6 can be selected in ⁶C₃ ways = 20

3 white balls out of 5 can be selected in ⁵C₃ ways = 10

3 blue balls out of 7 can be selected in ⁷C₃ ways = 35.

So, total number of ways of selecting 9 balls such that each selection

Consists of 3 balls of each colour which includes selecting 3 red and

selecting 3 white and selecting 3 blue balls  are 20*10*35

For more related question : https://brainly.in/question/7786310

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