Question

Example 3.8 Show that the radius of curvature at the point on the curvex = 3a
cose - a cos 30, y = 3a sin 8 - a sin 30 is 3a sin
x = 3a cos - acos 30; y = 3a sin 9 - a sin 38.​

Answer 1

it's 67 because of cos 36