Math, asked by shanibenny, 3 months ago

Example 3.8 Show that the radius of curvature at the point on the curvex = 3a
cose - a cos 30, y = 3a sin 8 - a sin 30 is 3a sin
x = 3a cos - acos 30; y = 3a sin 9 - a sin 38.​

Answers

Answered by guptaatulit01
0

it's 67 because of cos 36

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