Example 3
A die is thrown 250 times and the outcome is 1 2 3 4 5 6 frequency is 65 40 42 25 33 45. if a due is thrown at random, then find the probability of getting (i)1 (ii)2 (iii)3 (iv)4 (v)5 (vi)6
Answers
Answer:
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Step-by-step explanation:
Total number of trials = 250 In a random throw of a dia, let E 1 , E 2 , E 3 , E 4 , E 5 and E 6 E1,E2,E3,E4,E5andE6 be the events of getting 1, 2, 3, 4, 5 and 6, respectively. (i) P (getting 1) = P ( E 1 ) = number of times 1 appear total number of trials = 60 25 = 6 25 P (getting 1)=P(E1)=number of times 1 appeartotal number of trials=6025=625 (ii) P (getting 2) = P ( E 2 ) = number of times 2 appears total number of trials = 50 25 = 1 5 P (getting 2)=P(E2)=number of times 2 appearstotal number of trials=5025=15 (iii) P (getting 3) = P ( E 3 ) = number of times 3 appears total number of trials = 40 250 = 4 25 P (getting 3)=P(E3)=number of times 3 appearstotal number of trials=40250=425 (iv) P (getting 4) = P ( E 4 ) = number of times 4 appears total number of trials = 20 250 = 2 25 P (getting 4)=P(E4)=number of times 4 appearstotal number of trials=20250=225 (v) P (getting 5) = P ( E 5 ) = number of times 5 appears total number of trials = 30 250 = 3 25 Read more on Sarthaks.com - https://www.sarthaks.com/1135634/die-thrown-250-times-and-the-outcomes-are-noted-as-given-below-outcomes-frequency-40-if-die
Answer:
probability of getting 1: 65/250
" of getting of 2: 40/250
" of getting 3: 42/250
" of getting 4: 25/250
" of getting 5: 33/250
" of getting 6: 45/250
and then you can simplify it!