Question

Example 3: A kangaroo can jump 2.5 m
vertically. What must be the initial velocity
of the kangaroo?
Given :​

Answer 1

Explanation:

here it is given that kangaroo can jump to the height of 2.5m vertically

which implies kangaroos max height to jump is 2.5 m.

And kangaroo will jump making projectile.

therefore, max height in projectile:

= u^2 sin^2x/2g

where u= initial speed

x= angle of projection

as karoo jump to max height therefore angle of projection should be 90degree

hence max height = u^2/2g

putting value

2.5 = u^2/20. taking g= 10m/s^2

u= 5√2 m/s

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