Example 3: A kangaroo can jump 2.5 m
vertically. What must be the initial velocity
of the kangaroo? how acceleration is given in solution
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A kangaroo can jump 2.5 m vertically. What must be the initial velocity of the kangaroo? Given : a = 9.8 m/s? s = 2.5 m v = 0 C t u = ? I f v2= u? + 2as (0)2 = u’ + 2 × (-9.8) (2.5) Negative sign is used as the acceleration is in the direc- tion opposite to that of velocity. 0 = u? - 49 u? = 49 u = 7 m/s I C 11
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