Question

Example 3: A kangaroo can jump 2.5 m
vertically. What must be the initial velocity
of the kangaroo?​

Answer 1

Answer: Hope It Will Help You

Plz Mark As Brainliest Plz Explanation: a = 9.8 m/s?  s = 2.5 m  v = 0 C t  u = ?  I f v^2= u^2 + 2as  (0)2 = u^2 + 2 × (-9.8) (2.5) Negative sign is used as the acceleration is in the direc- tion opposite to that of velocity.  0 = u^2 - 49  u^2= 49

u = 7 m/s

Answer 2

Question :

A kangaroo can jump 2.5 m vertically. What must be the initial velocity  of the kangaroo?​

Given :

• v = 0

• a = 9.8 m/s²

• s = 2.5m

To Find :

The Initial Velocity 'u'

Formula Used :

$v^2=u^2+2as$

Solution :

Given that final velocity of the kangaroo is 0 (Since the velocity is at the highest point the final velocity is 0) , acceleration = 9.8 m/s² and distance = 2.5m.

Using third law of motion

$v^2=u^2+2as$

$0^2=u^2+2\times(-9.8)\times2.5\\\\\\0^2=u^2+(-49)\\\\\\0=u^2+(-49)\\\\\\u^2=49\\\\\\u=\sqrt{49} \\\\\\u=7m/sec$

Answer:

Initial Velocity of the Kangaroo = 7m/s

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