Question

Example 3: Factorise:
a. x2 + 6x + 8​

Answer 1

Answer:

x2+6x+8

x2+2x+4x+8

x(x+2)+4(x+2)

(x+4) (x+2)

Answer 2

Answer:

x^2+4x+2x+8(4+2=6 and 4*2=8)

x(x+4)+2(x+4)

(x+2)(x+4)

If the given expression has a value of zero,

then we can say that either

x+2=0 or x+4=0

Hence x can take 2 values which are -2 and -4.