Question

Example 3 : Find the zeroes of the polynomial x? - 3 and verify the relationship
between the zeroes and the coefficients.​

Answer 1

Answer:

Use the identity a2-b2=(a-b)(a+b)

x2-3 = (x-√3) (x+√3)

So , the value of x2 - 3 is zero when x = √3 or x = -√3

Therefore ,. the zeroes of x2-3 are √3 and -√3

Now,

Sum of zeroes = √3-√3=0 = -(Coefficient of x)/Coefficient of x2

Product of zeroes = (√3) (-√3) = -3 = -3/1 = Constant term/ Coefficient of x2