Question

Example 3 : Find the zeroes of the polynomial x2 - 3 and verify the relationship
between the zeroes and cofficients​

Answer 1

Step-by-step explanation:

please follow to this.....

hope it much helpful for you!

Answer 2

Step-by-step explanation:

the quadratic equation is x²+0x-3=0

x²-3=0

x² =3

x. =

+ \sqrt{3} . - \sqrt{3} +

3

.−

3

\alpha + \beta = - b \a \: \:α+β=−b\a

\sqrt{3} + - \sqrt{3} = 0 \1

3

+−

3

=0\1

then 0= 0

\alpha \times \beta = c \a α×β=c\a

\sqrt{3} \times - \sqrt{3} = - 3 \1

3

×−

3

=−3\1

-3=-3