Example 3: If the HCF and LCM of two numbers are 335 and 2010, then calculate
all the possible pairs of numbers.
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Step-by-step explanation:
if the hcf of two numbers in 335 . then the nos are multiple of 335.
Let the no.s be 335× and 335 y
As we know ,HCF×LCM= No. 1× No. 2
335 × 2010 = 335 × 335y
673350 = 112225 xy
673350/112225= xy
6= xy
now we will find such nos.which satisfies
the equation.
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