Question

Example 3 : PQ is a chord of length 8 cm of a
circle of radius 5 cm. The tangents at P and Q
intersect at a point T (see Fig. 4.10). Find the
length TP​

Answer 1

Answer:

Step-by-step explanation:

Let TR = y

Since OT is perpendicular bisector of PQ.

Therefore, PR=QR=4cm

In right triangle OTP and PTR, we have,

TP2=TR2+PR2

Also, OT2=TP2+OP2

OT2=(TR2+PR2) + OP2

(y+3)2=y2+16+25 (OR = 3, as OR2 = OP2 - PR2)

6y=32

y= 16/3

TP2=TR2+PR2

TP2= (16/3)sq+42 = 256/9+16 =  400/9

TP= 20/3 cm

hope this helps u..

Answer 2

Answer:

6 integer 2/3 cm

Step-by-step explanation:

hi ! your solution is attached here.

hope this helps you