Math, asked by vrushabh26, 10 months ago

Example 3: The population of a city two years
ago was 15,30,000. The population decreases by
20% the next year due to flood but increases by
10% the year after. Find the present population
of the city.​

Answers

Answered by haridasan85
5

2 yrs. ago population=I53oooo present Population

153oooox 80X120/loox 100 = =1468800

Answered by Thegreatsk
7

Answer:

The present population of the city is 13,46,400

Step-by-step explanation:

let total population = 100%

population decrease = 100-20 = 80%

So, population after the flood = 80% × no.

population

=80/100 × 15,30,000

=12,24,000

.: population after 1yr is 12,24,000

SIMILARLY

population increase => 100+10 = 110%

So, population after increasing = 110% ×

no. population

=110/100 × 12,24,000

=13,46,400

.: population after two years is 13,46,400

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