Question

Example 3. There are 156, 208 and 260 students in
groups A, B and C, respectively. Buses are to be hired
to take them for a field trip. Find the minimum number
of buses to be hired, if the same number of students
should be accommodated in each bus. CCE 2012; 11​

Answer 1

Answer:

You should take H.C.F. of 156, 208 and 260.

=> HCF of 156 and 208

P.F. of 156 = 2×2×3×13

P.F. of 208 = 2×2×2×2×13

Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52

=> Now , H.C.F. of 52 and 260

P.F. of 52 = 2×2×13

P.F. of 260 = 2×2×5×13

H.C.F. = 2×2×13 = 52

●Max. number of students per bus = 52

●Total number of students = 156+208+260 = 624 students.

●No. of buses = 624/52 = 12 buses.

NOW, MARK THIS ANS AS BRAINLIEST AND MAKE IT AS A VERIFIED ANSWER !!!!