Math, asked by philipjohnnson9848, 1 month ago

Example 3. Two runners cover the same distance at the rate of 15 km/h and 16 km/h
respectively. Find the distance travelled when one takes 16 minutes more than the
other.
Solution: Let the required distance be x km.
Time taken by the first runner to cover x km at 15 km/h = "h
15
Time taken by the second runner to cover x km at 16 km/h = -h
16
Now,
=
x x - 16
15 16 60
(I don't know
a I get 60 here)
or
16x - 15x 16
240 60
16x240 - 64
х
16
60
i.e., x =
or
240
60
.. The required distance is 64 km.​

Answers

Answered by Keerthy1802
0

Answer:

64 km

Step-by-step explanation:

Let the required distance be x km.

Time taken by the first runner to cover x km at 15 km/h = "h

15

Time taken by the second runner to cover x km at 16 km/h = -h

16

Now,

=

x x - 16

15 16 60

(I don't know

a I get 60 here)

or

16x - 15x 16

240 60

16x240 - 64

х

16

60

i.e., x =

or

240

60

.. The required distance is 64 km.​  

 

Answered by dksharma71977
0

Answer:

teri maa di madarchod math ka question deta hai bhenchod lad chusauga tujhe apni madarchod

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