Question

EXAMPLE 30 The digits of a positive integer, having three digits are in A.P. and their sum is 15.
The number obtained by reversing the digits is 594 less than the original number. Find the number
.
SOLUTION Let the digits at ones, tens and hundreds place be (a - d), a and (a + d)
respectively. Then, the number is
(a + d) x 100+ ax 10 + (a - d) = 111a + 99d
How this has come?​

Answer 1

Answer:

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