Question

Example 34. An electric field E is set up between the two
parallel plates of a capacitor, as shown in Fig. 1.40. Ant
electron enters the field symmetrically between the plates
with a speed vg. The length of each plate is I. Find the angle of
deviation of the path of the electron as it comes out of the field.​

Answer 1

Answer:

I hope I've described the figure alright.

As no electric field along x-axis, so v along x-axis remains constant.

Now, along y-axis, time required for electron to travel through capacitor is t= l/vg

Also, force, F along the E on electron is qE i.e eE.

So, acceleration, a= F/m = eE/m along y-axis.

Now, initially, vx = vg

and vy = uy + at

Since, uy= 0 (electron was introduced in x direction), then vy = at = eEl/mvg

So, angle of deviation, theta = tan^(-1) vy/vx = tan^(-1) eEl/m(vg)^2

Hope it helps.