Example 34 The masses m, m2 and m3
of the three bodies shown in Fig. 3(a).24 are 5,2
and 3 kg respectively. Calculate the values of
tension T1, T2 and T3 when (i) the whole system
is going upward with an acceleration of 2 m/s2
(ii) the whole system is stationary (g = 9.8 m/s2)
Answers
Answered by
5
Answer:
tension is 659 acceleration
Answered by
14
Explanation:
Given The masses m, m 2 and m 3 of the three bodies shown in Fig. 3(a).24 are 5,2 and 3 kg respectively. Calculate the values of
tension T1, T2 and T3 when (i) the whole system is going upward with an acceleration of 2 m/s2 (ii) the whole system is stationary (g = 9.8 m/s2)
- So the mass of m3 is 3 kg
- One force acting on it is T3 and another force is mg
- So mg = 3 x 9.8
- = 29.4 N
- So T3 = 29.4 N
- Also there is no force acting and the system is stationery.
- Now the weight of m2 is 2 kg
- One force acting on it is T2 and another is mg, one more force acting on it is T3
- So T2 = mg + T3
- = 2 x 9.8 + 29.4
- = 19.6 + 29.4
- = 49 N
- Now the weight of m1 is 5 kg
- One force acting on it is T1 and another is m1g, one more force acting on it is T2
- So T1 = m1g + T2
- = 5 x 9.8 + 49
- = 49 + 49
- = 98 N
- The weight of 3 masses is 3 kg, 2 kg and 5 kg. So the whole system is moving with an upward acceleration of 2 m/s^2
- So there will be pseudoforce and it will be m1a, m2a and m3 a
- Now we need to find T1,T2 and T3
- So in 3 kg block we have the forces T3, mg and ma
- So T3 = m(g + a)
- = 3 (9.8 + 2)
- = 3 x 11.8
- = 35.4 N
- Now taking two blocks as single system we have
- So mass will be m = 2 + 3 = 5 kg
- So the forces are T2, mg and ma
- Now mg = 5 x 9.8 = 49 N
- Now T2 = m (g + a)
- = 5(9.8 + 2)
- = 11.8 x 5
- = 59 N
- Now for T1 we have, forces are T1, mg and ma
- So total mass 5 + 3 + 2 = 10 kg
- So T1 = mg + ma
- = m(g + a)
- = 10 (9.8 + 2)
- = 10 x 11.8
- = 118 N
Reference link will be
https://brainly.in/question/5239574
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