Example 35: In a simple wheel and axle, the diameter of wheel is 150 mm and that of axle 30 mm. If the efficiency of the machine is 60%, determine the effort required to lift a load of 50 N. (S-94/4 M) - Data D = diameter of the wheel = 150 mm, d = diameter of the axle = 30 mm, m = 60 %, W = 50 N .
Answers
Answer:
boy divk come to see kxe eveb ccz
Answer:
The effort required is 10N.
Step-by-step explanation:
Given : In a simple wheel and axle the diameter of the effort wheel is 400 mm. The radii of the axles are 150 mm and 30 mm
To Find : the load which can be lifted by and effort of 50N assuming the efficiency of the machine to be 60%.
Solution:
Velocity ratio can be defined as the fraction of distance traveled by a body after the application of effort to that of the distance traveled by the load. In the wheel and axle case, the velocity ratio is the ratio of wheel radius to the axle radius.
The expression for the velocity ratio in wheel and axle system can be calculated as,
VR=rw/ra
VR=75/15
VR=5
The ideal mechanical advantage (IMA) will be equal to velocity ratio,
IMA=VR=5
The effort required to lift a load of
L=30N can be calculated as,
MA=LE
5=50/E
E=10N
Thus, the effort required is 10N.
Reference Link
- https://brainly.in/question/39884181
- https://brainly.in/question/23807430