Question

Example 4.4 The position of a particle is given by r = 3.0t i+2.0t?j+5.0 K where tis in seconds and the coefficients have the proper units for r to be in metres. (a) Find v(t) and a(t) of the particle. (b) Find the magnitude and direction of v(t) at t= 1.0 s.​

Answer 1

Answer:

Solution

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(a)  

v(t)=dr/dt

       =3.0i^−4.0tj^​

a(t)=dv(t)/dt

       =−4.0j^​

(b)  

v(2)=3.0i^−8.0j^​

v(2)=8.54m/s

∠v(2)=tan−1(−8/3)=−69.44∘with x axis