Science, asked by Dwivedivikash, 6 months ago

Example 4.9 A cricket ball is thrown at a
speed of 28 ms in a direction 30° above
Wone
is wh
equ
ovet
the horizontal. Calculate (a) the maximum
height. (b) the time taken by the ball to
return to the same level, and (c) the
distance from the thrower to the point
where the ball returns to the same level.
hvel​

Answers

Answered by sabirsayyad197361
1

Explanation:

Given : u=28 m/s θ=30

o

(a) : Maximum height H=

2g

u

2

sin

2

θ

⟹ H=

2×9.8

28

2

×0.5

2

=10 m

(b) : Time of flight T=

g

2usinθ

⟹ T=

9.8

2×28×sin30

=2.86 s

(c) : Range R=ucosθ×T

⟹ R=28×cos30

o

×2.86=69.27 m

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