Math, asked by AditiSah12, 10 months ago

Example 4: A sweetseller has 420 kaju barfis and 130 badam barfis. She wants to
stack them in such a way that each stack has the same number, and they take up the
least area of the tray. What is the number of that can be placed in each stack for this
purnose?​

Answers

Answered by Anonymous
2

Answer:

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Answered by rajnipriyadarshni
1

420>130

By division algorithm ,

H.C.F of 420 a d 130 is

420=130×3+30

130=30×4+10

30=10×3+0

H.C.F is 10

10 barfis can be placed in each stack

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