Question

Example-4. Find the zeroes of the polynomial x-3 and verify the relationship between the
zeroes and the coefficients.
Solution: Recall the identity a? - b2 = (a-6)(a+b).
doubt
Using it, we can write:
-3 = (x - 3)(x + V3 )
So, the value of x2 – 3 is zero when x = 3 or x = - V3.
Therefore, the zeroes of x2 – 3 are 13 and - 13
Sum of the zeroes
V3 +(-V3 ) = 0 =
-(coefficient of x)
coefficient of x2
-3
Product of zeroes
= (V3)*13)=- 3 =
constant term
coefficient of x2
1​

Answer 1

Answer:

the coefficient of V3 is 3