Question

Example-4. Find the zeroes of the polynomial x2 – 3 and verify the relationship between the
zeroes and the coefficients.
Solution : Recall the identity a? – 62 = (a - b)(a + b).
doubt
Using it, we can write:
(x² – 3 = (x - √3)(x + √3)
So, the value of x2 – 3 is zero when x = 13 or x = - 13.
Therefore, the zeroes of x2 – 3 are 13 and -13.
-(coefficient of x)
coefficient of x2
Sum of the zeroes
13+(-V3) = 0 =
constant term
coefficient of x2
Product of zeroes
-3
= (V3) (13)=- 3 =
1​

Answer 1

Answer:

Step-by-step explanation:

x²-3=0

=> x²-(√3)² =0

=> (x+√3)(x-√3)=0

=>x=√3,-√3

So the zeroes are√3 and-√3

Now sum of the zeroes=√3+(-√3)=0=0/1

Product of two zeroes=√3(-√3)=-3=-3/1.