Question

EXAMPLE 4 If x = log2a a, y = log3a 2a and z = log4a 3a, then
XYZ +1 =
(b) 2xy
(c) 2zx
(d) none of these
(a) 2yz
Ans(a)​

Answer 1

Answer:

xyz=loga/log2a×log2a/log3a×log3a/log4a

=loga/log4a

xyz+1=log4a²/log4a

=2×log2a/log4

=2×log2a/log3a×log3a/log4a

so answer is xyz+1=2yz